Oliver

10-26-2013, 04:52 AM

The point (4,3) is the midpoint of a line segment with endpoints at (-2,0) and one of the following:

(A) (10,6)

(B) (2,3)

(C) (6,0)

(D) (1,3)

Thanks!;)

(A) (10,6)

(B) (2,3)

(C) (6,0)

(D) (1,3)

Thanks!;)

View Full Version : midpoint formula

Oliver

10-26-2013, 04:52 AM

The point (4,3) is the midpoint of a line segment with endpoints at (-2,0) and one of the following:

(A) (10,6)

(B) (2,3)

(C) (6,0)

(D) (1,3)

Thanks!;)

(A) (10,6)

(B) (2,3)

(C) (6,0)

(D) (1,3)

Thanks!;)

nicole

10-26-2013, 04:53 AM

The midpoint formula for x and y coordinates is given below:

x_{m}=\frac{ x_{1}+ x_{2}}{2} and y_{m}=\frac{ y_{1}+ y_{2}}{2}

where (x_{m}, y_{m}) are the coordinates of the midpoint and (x_{1}, y_{1}) ,\ (x_{2}, y_{2}) are the endpoints.

So, 4=\frac{ -2+ x_{2}}{2} and 3=\frac{ 0+ y_{2}}{2}

-2+ x_{2}=8 and y_{2}=6

x_{2}=10 and y_{2}=6

Therefore the correct answer is (A).

Hope these help!!

x_{m}=\frac{ x_{1}+ x_{2}}{2} and y_{m}=\frac{ y_{1}+ y_{2}}{2}

where (x_{m}, y_{m}) are the coordinates of the midpoint and (x_{1}, y_{1}) ,\ (x_{2}, y_{2}) are the endpoints.

So, 4=\frac{ -2+ x_{2}}{2} and 3=\frac{ 0+ y_{2}}{2}

-2+ x_{2}=8 and y_{2}=6

x_{2}=10 and y_{2}=6

Therefore the correct answer is (A).

Hope these help!!

Oliver

10-26-2013, 04:54 AM

Thanks Nicole!

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