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Jack
10-10-2013, 11:09 AM
If 1<x <2, then how can we find the possible values that the expression (x-2)^2+x can take?

miranda
10-10-2013, 11:10 AM
using inequalities
1-2<x-2 < 2-2
-1<x-2 < 0
0<(x-2)^2 < 1 (1)
and
1<x < 2 (2)
Adding (1) and (2) we have
0+1<(x-2)^2+x < 1+2
1<(x-2)^2+x < 3

hope these help!

Jack
10-10-2013, 11:11 AM
Thanks miranda!