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Thread: SAT Operations inside parentheses

  1. #1
    Junior Member
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    Jun 2013
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    SAT Operations inside parentheses

    SAT math - Number and Operations

    How can we find the result of the following expression:

    (2-(3-(1-(2-(4-3)))))-(2-(3-(1-(2-(4+3)))))

    Thanks!

  2. #2
    Quote Originally Posted by Brynlee View Post
    SAT math - Number and Operations

    How can we find the result of the following expression:

    (2-(3-(1-(2-(4-3)))))-(2-(3-(1-(2-(4+3)))))

    Thanks!
    Brynlee you have to work from the innermost to the outermost parentheses

    (2-(3-(1-(2-(4-3)))))=(2-(3-(1-(2-(-1)))))=(2-(3-(1-(2+1))))=(2-(3-(1-3)))=(2-(3-(-2)))=(2-(3+2))=(2-5)=-3

    and the rightmost expression is

    (2-(3-(1-(2-(4+3)))))=(2-(3-(1-(2-(7)))))=(2-(3-(1-(-5))))=(2-(3-(1+5)))=(2-(3-(6)))=(2-(-3))=(2+3)=5

    So the final result is (-3)-5=-8

    Hope these help!!

  3. #3
    Junior Member
    Join Date
    Jun 2013
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    Thanks miranda!

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